12/(x^2+x-2)-(x+3)/(x-1)=(1-x)/(x+2)

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Solution for 12/(x^2+x-2)-(x+3)/(x-1)=(1-x)/(x+2) equation:


D( x )

x+2 = 0

x^2+x-2 = 0

x-1 = 0

x+2 = 0

x+2 = 0

x+2 = 0 // - 2

x = -2

x^2+x-2 = 0

x^2+x-2 = 0

x^2+x-2 = 0

DELTA = 1^2-(-2*1*4)

DELTA = 9

DELTA > 0

x = (9^(1/2)-1)/(1*2) or x = (-9^(1/2)-1)/(1*2)

x = 1 or x = -2

x-1 = 0

x-1 = 0

x-1 = 0 // + 1

x = 1

x in (-oo:-2) U (-2:1) U (1:+oo)

12/(x^2+x-2)-((x+3)/(x-1)) = (1-x)/(x+2) // - (1-x)/(x+2)

12/(x^2+x-2)-((x+3)/(x-1))-((1-x)/(x+2)) = 0

12/(x^2+x-2)+(-1*(x+3))/(x-1)+(-1*(1-x))/(x+2) = 0

x^2+x-2 = 0

x^2+x-2 = 0

x^2+x-2 = 0

DELTA = 1^2-(-2*1*4)

DELTA = 9

DELTA > 0

x = (9^(1/2)-1)/(1*2) or x = (-9^(1/2)-1)/(1*2)

x = 1 or x = -2

(x+2)*(x-1) = 0

12/((x+2)*(x-1))+(-1*(x+3))/(x-1)+(-1*(1-x))/(x+2) = 0

12/((x+2)*(x-1))+(-1*(x+3)*(x+2))/((x+2)*(x-1))+(-1*(1-x)*(x-1))/((x+2)*(x-1)) = 0

12-1*(x+3)*(x+2)-1*(1-x)*(x-1) = 0

x^2-x^2-5*x-2*x+1+6 = 0

7-7*x = 0

(7-7*x)/((x+2)*(x-1)) = 0

(7-7*x)/((x+2)*(x-1)) = 0 // * (x+2)*(x-1)

7-7*x = 0

7-7*x = 0 // - 7

-7*x = -7 // : -7

x = -7/(-7)

x = 1

x in { 1}

x belongs to the empty set

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